| bio | website | dotnetdust.blogspot.com |
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| location | Indianapolis, IN | |
| age | 29 | |
| visits | member for | 11 months |
| seen | Apr 14 at 3:21 | |
| stats | profile views | 11 |
Senior Consultant at http://www.allegient.com/.
Specializing in C# and Microsoft Dynamics CRM 2011
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Apr 10 |
awarded | Autobiographer |
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Jun 22 |
awarded | Scholar |
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Jun 22 |
awarded | Editor |
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Jun 22 |
accepted | How do I create a redstone circuit whose output depends on it's previous input? |
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Jun 22 |
revised |
How do I create a redstone circuit whose output depends on it's previous input? Added Solution |
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Jun 21 |
comment |
How do I create a redstone circuit whose output depends on it's previous input? I'm not seeing how this works... What is my Clock tick, and how to I convert the registers into my output? |
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Jun 21 |
comment |
How do I create a redstone circuit whose output depends on it's previous input? I think I'm understanding a little of what your talking about, but in my mind MBraedley's would scale better as I add more inputs. Am I wrong in that assumption? |
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Jun 21 |
comment |
How do I create a redstone circuit whose output depends on it's previous input? I think I understand. Each input will need it's own rising and falling edge detector. I then OR all of the rising detectors together, and OR all of the falling edge detectors together, so I end up with one rising detector signal, and one falling detector signal, which I can combine into an RS NOR latch. |
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Jun 21 |
awarded | Supporter |
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Jun 21 |
comment |
How do I create a redstone circuit whose output depends on it's previous input? @John I'm using this design specifically since it is the fastest I have found and is more reliable than the Villager version of light detectors: youtube.com/watch?v=zdMA8B50DVk&feature=plcp |
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Jun 21 |
comment |
How do I create a redstone circuit whose output depends on it's previous input? @QAdley I didn't bother with the (1, 0) (A, B) states since they are identical to the (0,1) states. |
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Jun 21 |
awarded | Student |
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Jun 21 |
asked | How do I create a redstone circuit whose output depends on it's previous input? |