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added 270 characters in body
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Amy B
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Put Steve in a 1x1 hole and measure the wiggle room. ALL the room - WiggleRoom = Steve


In a 1x1 hole, I pointed the camera straight down and moved from corner to corner. Regardless of corner or orientation, the crosshairs pointed at the farthest point of a 5x5 square from the corner.

16 = 5 + 6 + 5

That's 16 total square width, 5 for the each side of Steve, and 6 for the wiggle room.

Front/back/left/right, the closest you can get to a wall is 5. This test is unable to confirm if Steve is 10x10 square, or a 5 radius circle.


Note: this finding contradicts the original question, as Steve is 0.625 wide, and the asker was expecting more than that. However the original question also supports this answer in the door screenshot (5 texture pixels from door).

It seems reasonable to think that Steve is an unrotating 0.625x0.625 square, which is 0.88 from corner to corner, and could not fit through the ~0.7 gap.


Here is Steve (in green), blocked by two stairs (in purple). Steve is 10 units big, but the yellow line is ~14.14 units big, which is too large to go through the ~11.3 unit opening.

Steve trapped

Put Steve in a 1x1 hole and measure the wiggle room. ALL the room - WiggleRoom = Steve


In a 1x1 hole, I pointed the camera straight down and moved from corner to corner. Regardless of corner or orientation, the crosshairs pointed at the farthest point of a 5x5 square from the corner.

16 = 5 + 6 + 5

That's 16 total square width, 5 for the each side of Steve, and 6 for the wiggle room.

Front/back/left/right, the closest you can get to a wall is 5. This test is unable to confirm if Steve is 10x10 square, or a 5 radius circle.


Note: this finding contradicts the original question, as Steve is 0.625 wide, and the asker was expecting more than that. However the original question also supports this answer in the door screenshot (5 texture pixels from door).

It seems reasonable to think that Steve is an unrotating 0.625x0.625 square, which is 0.88 from corner to corner, and could not fit through the ~0.7 gap.

Put Steve in a 1x1 hole and measure the wiggle room. ALL the room - WiggleRoom = Steve


In a 1x1 hole, I pointed the camera straight down and moved from corner to corner. Regardless of corner or orientation, the crosshairs pointed at the farthest point of a 5x5 square from the corner.

16 = 5 + 6 + 5

That's 16 total square width, 5 for the each side of Steve, and 6 for the wiggle room.

Front/back/left/right, the closest you can get to a wall is 5. This test is unable to confirm if Steve is 10x10 square, or a 5 radius circle.


Note: this finding contradicts the original question, as Steve is 0.625 wide, and the asker was expecting more than that. However the original question also supports this answer in the door screenshot (5 texture pixels from door).

It seems reasonable to think that Steve is an unrotating 0.625x0.625 square, which is 0.88 from corner to corner, and could not fit through the ~0.7 gap.


Here is Steve (in green), blocked by two stairs (in purple). Steve is 10 units big, but the yellow line is ~14.14 units big, which is too large to go through the ~11.3 unit opening.

Steve trapped

added 391 characters in body; added 17 characters in body
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Amy B
  • 22.4k
  • 9
  • 75
  • 124

Put Steve in a 1x1 hole and measure the wiggle room. ALL the room - WiggleRoom = Steve


In a 1x1 hole, I pointed the camera straight down and moved from corner to corner. Regardless of corner or orientation, the crosshairs pointed at the farthest point of a 5x5 square from the corner.

16 = 5 + 6 + 5

That's 16 total square width, 5 for the each side of Steve, and 6 for the wiggle room.

Front/back/left/right, the closest you can get to a wall is 5. This test is unable to confirm if Steve is 10x10 square, or a 5 radius circle.


Note: this finding contradicts the original question, as Steve is 0.625 wide, and the asker was expecting more than that. However the original question also supports this answer in the door screenshot (5 texture pixels from door).

It seems reasonable to think that Steve is an unrotating 0.625x0.625 square, which is 0.88 from corner to corner, and could not fit through the ~0.7 gap.

Put Steve in a 1x1 hole and measure the wiggle room. ALL the room - WiggleRoom = Steve


In a 1x1 hole, I pointed the camera straight down and moved from corner to corner. Regardless of corner or orientation, the crosshairs pointed at the farthest point of a 5x5 square from the corner.

16 = 5 + 6 + 5

That's 16 total square width, 5 for the each side of Steve, and 6 for the wiggle room.

Front/back/left/right, the closest you can get to a wall is 5. This test is unable to confirm if Steve is 10x10 square, or a 5 radius circle.

Put Steve in a 1x1 hole and measure the wiggle room. ALL the room - WiggleRoom = Steve


In a 1x1 hole, I pointed the camera straight down and moved from corner to corner. Regardless of corner or orientation, the crosshairs pointed at the farthest point of a 5x5 square from the corner.

16 = 5 + 6 + 5

That's 16 total square width, 5 for the each side of Steve, and 6 for the wiggle room.

Front/back/left/right, the closest you can get to a wall is 5. This test is unable to confirm if Steve is 10x10 square, or a 5 radius circle.


Note: this finding contradicts the original question, as Steve is 0.625 wide, and the asker was expecting more than that. However the original question also supports this answer in the door screenshot (5 texture pixels from door).

It seems reasonable to think that Steve is an unrotating 0.625x0.625 square, which is 0.88 from corner to corner, and could not fit through the ~0.7 gap.

added 466 characters in body; added 4 characters in body
Source Link
Amy B
  • 22.4k
  • 9
  • 75
  • 124

Put Steve in a 1x1 hole and measure the wiggle room. ALL the room - WiggleRoom = Steve


In a 1x1 hole, I pointed the camera straight down and moved from corner to corner. Regardless of corner or orientation, the crosshairs pointed at the farthest point of a 5x5 square from the corner.

16 = 5 + 6 + 5

That's 16 total square width, 5 for the each side of Steve, and 6 for the wiggle room.

Front/back/left/right, the closest you can get to a wall is 5. This test is unable to confirm if Steve is 10x10 square, or a 5 radius circle.

Put Steve in a 1x1 hole and measure the wiggle room. ALL the room - WiggleRoom = Steve

Put Steve in a 1x1 hole and measure the wiggle room. ALL the room - WiggleRoom = Steve


In a 1x1 hole, I pointed the camera straight down and moved from corner to corner. Regardless of corner or orientation, the crosshairs pointed at the farthest point of a 5x5 square from the corner.

16 = 5 + 6 + 5

That's 16 total square width, 5 for the each side of Steve, and 6 for the wiggle room.

Front/back/left/right, the closest you can get to a wall is 5. This test is unable to confirm if Steve is 10x10 square, or a 5 radius circle.

Post Undeleted by Amy B
deleted 180 characters in body; deleted 1 characters in body
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Amy B
  • 22.4k
  • 9
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  • 124
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Amy B
  • 22.4k
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  • 124
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