First of all, I would like to assure you that I have done my homework when it comes to understanding damage calculation in Monster Hunter. My question is somewhat advanced because understanding damage calculation is a prerequisite.
Total Damage Output = ([Physical Damage Output] + [Elemental Damage Output]) * Overall Defense
And of course it gets more complicated than that.
My question is on the calculation of the
Elemental Damage Output for, say, a Light Bowgun. Most weapons in the game have a stat called
Element, which shows the
Elemental attack of the weapon. This value is used in the computation of the
Elemental Damage Output as follows:
Elemental Damage Output = (Elemental attack / 10) * Elemental effectiveness
The problem with bowguns is that they do not have any
Element stat. So as I looked into the question (I told you I did my homework ^^), I found out that the
Element stat for bowguns was contained within elemental shots (e.g. Flaming S, Water S, ...). For example, according to this beautifully written tutorial on bowguns that I urge every aspiring gunners to read, the stats on
Flaming S is
7 + 45 Fire and I would like to know what it means:
I think the
7is the motion value used to calculate the
Physical damage outputso that it will be 7% of the weapon's
effective power(which takes into account the
raw damage, the
weapon factorand the
affinity. Please, correct me if I'm wrong.
I don't know what to think about the
45 Firedamage. If such a small value is used as the
Elemental attackin the
Elemental Damage Outputcalculation (in the formula above), it makes no sense because bowguns would be severely disadvantaged because the actual elemental damage dealt would be 4.5 times some elemental effectiveness, which is usually a low percentage. So, this interpretation is likely not correct. Or am I to see the
45 Firedamage as the result of
450 / 10, which then needs to be multiplied by the
Your help is greatly appreciated.