9

I have a long underground path in my park. I want to add a bathroom to this road underground. Is this possible in RCT1? And how?

  • 10
    I don't think that's possible. But you can dig a hole and build the toilet inside (and cover the hole with a road) if you want. – Nolonar Dec 5 '16 at 11:45
  • Not exactly what I was hoping for. Thanks for your answer. – Maiko Kingma Dec 5 '16 at 11:46
  • 1
    You cannot have a ground surface above buildings, so Nolonar's answer is correct. I've often wished for the same as you, though... – NGCaptainM Dec 6 '16 at 19:57
  • 2
    @Nolonar Any reason you made that a comment and not an answer? It seems like the accepted answer here – Stevoisiak Apr 28 '17 at 1:37
  • 2
    @StevenVascellaro. Because I no longer have access to the game, I can't verify if my answer is actually correct or not. – Nolonar May 7 '17 at 14:21
6

In the original release of RCT1, this is not possible as you can only build tracked rides and pathways underground, and that is if they start above-ground first (you can start building above-ground and then remove the above-ground track once the ride goes underground. Attractions such as shops, toilets and single-piece gentle rides cannot be placed underground for that reason.

In RCT2 and the Android re-release of RCT, you can move an attraction underground using the shift key and the onscreen arrow controls respectively.

| improve this answer | |
2

It's been a while, but in two of the scenarios in base RCT there are completely underground rides - rollercoasters specifically. I don't think placing non-tracked rides like the merry go round or shops was allowed.

To achieve this you build your ride and then lower the ground underneath causing it to "close over". That's what I remember at least, doing things underground could be a pain at best.

| improve this answer | |

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.