3

Exactly what is said on the tin. I couldn't find sufficient information on the official wiki to determine this statistic.

  • 1
    The average-sized one, according to my experience, has 2-7 chests, usually 4 or 5 – RudolfJelin Dec 15 '17 at 14:35
10

About 5 ½

With a bit of command help, I was able to explore a variety of randomly generated Mineshafts and instantly get the total number of chest Minecarts, by detecting them as entities (minecraft:chest_minecart). After visiting a few tens of Mineshafts (>40), I was able to extrapolate some average stats per Mineshaft, including spawner rates:

  • 5½ chest Minecarts (for comparison - about 1.5 gold apples per complex)
  • a median of 5 chests, with ~80% of the Mineshafts having 3-9 chests
  • about 3 spawners

A not-so-accurate graph of the probability to find the given count of chests:

No, this is NOT paint

The blue line represents the actual statistics, the yellow one the ideal probability values. Since the total number of mineshafts is 44 (low for accurate stats, but good for rough calculations), the chance to find, let's say, exactly 5 chests is (~7/44) * 100 ≈ 15%

You can also find no minecarts at all - the chances for this are quite high (just under one from ten). Finding over 12 is rare. In practice, one will locate averagely around 4-5 chests, with some remaining unlooted.

| improve this answer | |
-1

Chests are randomly generated within each mine shaft wing. There is no equation or figure as to "How Many Chests are in a mine shaft" Mine shafts can vary in sizes. A small mine shaft may have 3 chests but a large one may have none.

| improve this answer | |
  • 1
    Once could still give an average value, though. However, it will probably loose some meaning, as the size of Mineshafts varies as you said. More interesting would be the average density, i.e. the average amount divided by the size. But still an average amount makes sense, as it would just include an averaging of the sizes. – RimaNari Dec 16 '17 at 15:38

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.