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I would like to make a circuit with one lever input and two outputs. When the user flips the lever, I would like for the one output that's ON to immediately turn OFF, while the other output which is OFF takes a second or two to turn ON. Both outputs should behave the same way such that when the lever is flipped again, the exact same thing happens, but with the outputs swapped. I'm currently accomplishing this with two AND gates like so:

But I'm looking for a much more compact way of doing it. Any thoughts?

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  • Is a 4 tick delay enough then, or would you like more of a delay?
    – fredley
    Dec 12, 2012 at 17:18
  • A simple way to compact the horizontal space taken up by this mechanism would be to put the two and gates on top of each other
    – fredley
    Dec 12, 2012 at 17:27

4 Answers 4

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enter image description here

This is a very compact solution. The torches on the right are the two outputs.

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    Very impressive
    – fredley
    Dec 13, 2012 at 11:04
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**I like your design, but when tried it out, I made my own, more compact version. You might even be able to make it more compact by shortening the length of the redstone leading up to the outputs, and moving the outputs back one block. Glad to help!**

I like your design, but when tried it out, I made my own, more compact version. You might even be able to make it more compact by shortening the length of the redstone leading up to the outputs, and moving the outputs back one block.

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Delayed ON-Instant OFF

I made this Delayed ON-Instant OFF thing using an AND Gate with one side delayed. I'm answering this now because I was searching for this and ended up here. So I made my own solution for those who may get here as well

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I made a 3x5 one. It is extremely compact and effective. Screenshot of circuit

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