17

If I somehow give Windfury to this pretty boy

enter image description here

(for example by getting Windfury from an enemy mage playing a Spellslinger), what is going to happen if I kill one of the opponent's minions? Do I get two more attacks? Or is the additional attack from Windfury wasted in this case?

2
  • My guess would be it just adds another 'normal' attack, so windfury would just be pushed back. Interesting question for science, though
    – two bugs
    Commented May 10, 2016 at 12:25
  • @twobugs definitely doing it for science, the chance of this happening is VERY low, but it still could be an interesting interaction
    – Kappei
    Commented May 10, 2016 at 12:32

1 Answer 1

13

It can attack the opposing hero twice and any number of minions before. (As long as it kills them.) I tested this in a practice game via Enhance-o Mechano.

Before attacks: enter image description here

After first (minion) and second attack (hero): enter image description here

After third (minion) and fourth attack (hero): enter image description here

3
  • 2
    So potentially it could "double tap" an opposing big minion to kill it, then keep attacking afterwards. Thanks for testing this out!
    – Kappei
    Commented May 10, 2016 at 12:55
  • After it killed a minion with it's 3rd attack shouldn't it of chained into a 5th attack? Since the card says "whenever it attacks and kills a minion". The order of chaining seemed to be going base -> windfury -> bonus base -> windfury. Even in the situation where it goes base -> bonus base -> windfury -> bonus base, it seems like that last bonus base should of triggered another windfury.
    – Ryan
    Commented May 10, 2016 at 20:30
  • This wasn't on the wiki, so I added it as a reference. Thanks! hearthstone.gamepedia.com/Giant_Sand_Worm#Notes
    – Patashu
    Commented Jun 23, 2016 at 6:54

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.