Bending a conditional chain

Question

As we all know, you can't bend a chain of conditional command blocks. Many people have had problems with this and I'm perfectly aware of why it doesn't work by just, placing the blocks in a different pattern.

However, I know it's possible. Whether through some /stats command or testing for a SuccessCount tag at the bend (not too sure on how either of these work as I've never had to use them)... What's the most simple way of doing this?

Edit:

This is what I've tried so far.

So, 1 won't execute even though it's being "powered" by the block next to it in the chain, because there's nothing behind it to provide check for a successful execution.

3 won't execute despite having what 1 lacks, because nothing's "triggering" it. (I tried to put a repeat block in the empty spot of 2 to power 3 but of course that gets rerouted by the block between 2 and 3.)

What I was considering was having a repeat block in place of 4 testing if the block between 2 and 3 is successful, then having that block trigger 1 and having the met condition come from 4. But I suppose there's a more simple way of doing it, with less command blocks (after all you would have to reset the SuccessCount after every execution, right?).

So, I hope that's enough effort and whatever for you people, I expect to see this question at the top of Google later. Thank you! :D

Answer 1

For simplicity and speed, I'd do it something like this:

The unconditional blocks outlined in red can be left blank, and are just there to continue on the chain. The next block still depends conditionally on the previous conditional block.

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Alternatively, for one less command block, you can do:

In which the blue outlined block has the command:

/testforblock ~1 ~ ~ chain_command_block -1 {SuccessCount:1}

Replacing ~1 ~ ~ with the offset for the previous block in the chain.

Answer 2

Oops, I forgot to mention that the first block in the chain is a repeat block. :P

Here's my solution:

Just have the first block going the other direction power itself.

Thanks again, smart people.